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[BOJ] 23단계 누적 합

kinggora 2023. 5. 3. 23:56
1 11659 구간 합 구하기 4
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(reader.readLine());
        int N = Integer.parseInt(tokenizer.nextToken());
        int M = Integer.parseInt(tokenizer.nextToken());

        int[] sum = new int[N + 1];
        sum[0] = 0;

        tokenizer = new StringTokenizer(reader.readLine());
        for(int i = 1; i <= N; i++) {
            sum[i] = sum[i-1] + Integer.parseInt(tokenizer.nextToken());
        }

        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < M; i++) {
            tokenizer = new StringTokenizer(reader.readLine());
            int a = Integer.parseInt(tokenizer.nextToken());
            int b = Integer.parseInt(tokenizer.nextToken());
            sb.append(sum[b] - sum[a-1]).append("\n");
        }
        System.out.print(sb);
    }

}

*입력과 동시에 이전 항의 누적 합을 이용하여 현재 항의 누적 합을 초기화한다.

*1번째 수의 누적합을 다른 누적합과 동일한 방식으로 처리하기 위해 sum 배열의 크기를 N+1로 했다.

 

2 2559 수열

연속적인 K개의 부분 수열의 합이 최대가 되는 값

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(reader.readLine());
        int N = Integer.parseInt(tokenizer.nextToken());
        int K = Integer.parseInt(tokenizer.nextToken());

        int[] prefixSum = new int[N + 1];
        prefixSum[0] = 0;

        tokenizer = new StringTokenizer(reader.readLine());
        for(int i = 1; i <= N; i++) {
            prefixSum[i] = prefixSum[i-1] + Integer.parseInt(tokenizer.nextToken());
        }

        int max = Integer.MIN_VALUE;
        for(int i = K; i <= N; i++) {
            max = Math.max(prefixSum[i] - prefixSum[i - K], max);
        }
        System.out.println(max);
    }
}

 

3 16139 인간-컴퓨터 상호작용

 

4 10986 나머지 합

 

5 11660 구간 합 구하기 5
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(reader.readLine());
        int N = Integer.parseInt(tokenizer.nextToken());
        int M = Integer.parseInt(tokenizer.nextToken());

        int[][] sum = new int[N][N + 1];

        for(int i = 0; i < N; i++) {
            tokenizer = new StringTokenizer(reader.readLine());
            for(int j = 1 ; j <= N; j++) {
                sum[i][j] = sum[i][j-1] + Integer.parseInt(tokenizer.nextToken());
            }
        }

        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < M; i++) {
            tokenizer = new StringTokenizer(reader.readLine());
            int x1 = Integer.parseInt(tokenizer.nextToken());
            int y1 = Integer.parseInt(tokenizer.nextToken());
            int x2 = Integer.parseInt(tokenizer.nextToken());
            int y2 = Integer.parseInt(tokenizer.nextToken());

            int result = 0;
            for(int j = x1 - 1; j < x2; j++) {
                result += sum[j][y2] - sum[j][y1 - 1];
            }
            sb.append(result).append("\n");
        }
        System.out.print(sb);
    }

}

*sum[i][]: i행 별 누적합 계산

 

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(reader.readLine());
        int N = Integer.parseInt(tokenizer.nextToken());
        int M = Integer.parseInt(tokenizer.nextToken());

        int[][] arr = new int[N + 1][N + 1];
        int[][] dp = new int[N + 1][N + 1];

        for(int i = 1; i <= N; i++) {
            tokenizer = new StringTokenizer(reader.readLine());
            for(int j = 1 ; j <= N; j++) {
                arr[i][j] = Integer.parseInt(tokenizer.nextToken());
            }
        }
        for(int i = 1; i <= N; i++) {
            for(int j = 1 ; j <= N; j++) {
                dp[i][j] = dp[i][j-1] + dp[i-1][j] - dp[i-1][j-1] + arr[i][j];
            }
        }

        StringBuilder sb = new StringBuilder();
        for(int i = 0; i < M; i++) {
            tokenizer = new StringTokenizer(reader.readLine());
            int x1 = Integer.parseInt(tokenizer.nextToken());
            int y1 = Integer.parseInt(tokenizer.nextToken());
            int x2 = Integer.parseInt(tokenizer.nextToken());
            int y2 = Integer.parseInt(tokenizer.nextToken());

            int result = dp[x2][y2] - dp[x2][y1-1] - dp[x1-1][y2] + dp[x1-1][y1-1];
            sb.append(result).append("\n");
        }
        System.out.print(sb);
    }

}

*dp[i][j]: (1,1)부터 (i,j)까지의 누적 합 계산

 

6 25682 체스판 다시 칠하기 2
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Main {

    public static void main(String[] args) throws IOException {
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer tokenizer = new StringTokenizer(reader.readLine());
        int N = Integer.parseInt(tokenizer.nextToken());
        int M = Integer.parseInt(tokenizer.nextToken());
        int K = Integer.parseInt(tokenizer.nextToken());

        int[][] startW = new int[N+1][M+1];
        int[][] startB = new int[N+1][M+1];
        for(int i = 1; i <= N; i++) {
            String str = reader.readLine();
            for(int j = 1; j <= M; j++) {
                if((i + j) % 2 == 0) {
                    if(str.charAt(j-1) == 'W') {
                        startB[i][j] = 1;
                    } else {
                        startW[i][j] = 1;
                    }
                } else {
                    if(str.charAt(j-1) == 'W') {
                        startW[i][j] = 1;
                    } else {
                        startB[i][j] = 1;
                    }
                }
            }
        }

        int dpW[][] = new int[N+1][M+1];
        int dpB[][] = new int[N+1][M+1];
        for(int i = 1; i <= N; i++) {
            for(int j = 1; j <= M; j++) {
                dpW[i][j] = dpW[i][j-1] + dpW[i-1][j] - dpW[i-1][j-1] + startW[i][j];
                dpB[i][j] = dpB[i][j-1] + dpB[i-1][j] - dpB[i-1][j-1] + startB[i][j];
            }
        }

        int min = Integer.MAX_VALUE;
        for(int i = K; i <= N; i++) {
            for(int j = K; j <= M; j++) {
                int w = dpW[i][j] - dpW[i][j - K] - dpW[i - K][j] + dpW[i - K][j - K];
                int b = dpB[i][j] - dpB[i][j - K] - dpB[i - K][j] + dpB[i - K][j - K];
                min = Math.min(Math.min(w,b), min);
            }
        }
        System.out.println(min);
    }

}